Asked by shari
factor completely (q-4)^2-144
Answers
Answered by
Anonymous
in general
a^2 - b^2 = (a-b)(a+b)
so
(q-4)^2 - 12^2
= [(q-4) - 12] [ (q-4) + 12]
= (q-16)(q+8)
a^2 - b^2 = (a-b)(a+b)
so
(q-4)^2 - 12^2
= [(q-4) - 12] [ (q-4) + 12]
= (q-16)(q+8)
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