If you need help solving for x, then find a common denominator, just as you would with numeric fractions. That would be (x-2)(x+1). So,
(x)/(x-2)+(x-1)/(x+1)=1
x(x+1) + (x-1)(x-2) = (x-2)(x+1)
x^2-x+4 = 0
now solve for x in the usual way.
(x)/(x-2)+(x-1)/(x+1)=1
I need help plz.
2 answers
Multiply all terms by (x-2)(x+1)
x(x+1)+(x−1)(x−2) = 1(x−2)(x+1)
2x^2−2x+2 = x^2−x−2
Subtract x^2-x-2 from both sides
2x^2−2x+2−(x^2−x−2) = x^2−x−2−(x^2−x−2)
x^2−x+4 = 0
The solutions are:
x = ( 1 ± i √15 ) / 2
x(x+1)+(x−1)(x−2) = 1(x−2)(x+1)
2x^2−2x+2 = x^2−x−2
Subtract x^2-x-2 from both sides
2x^2−2x+2−(x^2−x−2) = x^2−x−2−(x^2−x−2)
x^2−x+4 = 0
The solutions are:
x = ( 1 ± i √15 ) / 2