Asked by Hiba
2)_ To prepare a buffer solution with a pH of 3.45 What should be the mass of Sodium mandelate that should be added to 500ml of 1.00M mandelic acid solution?
Answers
Answered by
DrBob222
Use the H-H equation. You will need to look pKa for mandelic aci
pH = pKa + log [(base)/(acid)] or pKa + log (b)/(a)
3.45 = pKa + log (b)/(1)
Solve for (b) in millimoles/mL = M. You've solved for M and you have mL (100 mL) so you solve for millimoles. Convert to mols and remember mol = grams/molar mass. You have molar mass and mols, calculate grams and you have it.
pH = pKa + log [(base)/(acid)] or pKa + log (b)/(a)
3.45 = pKa + log (b)/(1)
Solve for (b) in millimoles/mL = M. You've solved for M and you have mL (100 mL) so you solve for millimoles. Convert to mols and remember mol = grams/molar mass. You have molar mass and mols, calculate grams and you have it.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.