I like to work in millimoles to keep the zeros to a minimum.
millimoles = mL x M = ?
2 K3PO4 + 3 MgCl2 → Mg3(PO4)2 + 6 KCl
millimoles MgCl2 = 26 x 0.453 = 11.78
Convert to millimoles K3PO4 using the coefficients in the balanced equation.
11.78 mmols MgCl2 x (2 mols K3PO4/3 mols MgCl2) = 11.78 x 2/3 = 7.85
Then M = millimoles/mL = ? You have M and mmoles, substitute and solve for mL K3PO4.
What volume of 0.649 M K3PO4 is required to react with 26 mL of 0.453 M MgCl2 according to the equation
2 K3PO4 + 3 MgCl2 → Mg3(PO4)2 + 6 KCl Answer in units of mL.
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