Asked by Kaur
If x+y+z=7 and
1/x + 1/y + 1/z =10+xyz ,then find the value of x^2+y^2+z^2+1
1/x + 1/y + 1/z =10+xyz ,then find the value of x^2+y^2+z^2+1
Answers
Answered by
Anonymous
(x+y+z)^2 = x^2+y^2+z^2 + 2xy+2xz+2yz = 7^2
x^2+y^2+z^2 + 2xyz (xy+xz+yz)/xyz = 49
x^2+y^2+z^2 + 2xyz (1/z + 1/y + 1/x) = 49
see what you can do with that.
x^2+y^2+z^2 + 2xyz (xy+xz+yz)/xyz = 49
x^2+y^2+z^2 + 2xyz (1/z + 1/y + 1/x) = 49
see what you can do with that.
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