The random variable X has a PDF of the form
fX(x)= 1/x^2,for x≥1,
0,otherwise.
Let Y=X2. For y≥1, the PDF of Y it takes the form fY(y)=a / y^b. Find the values of a and b.
1 answer
a = 1/2 and b = 3
fX(x)= 1/x^2,for x≥1,
0,otherwise.
Let Y=X2. For y≥1, the PDF of Y it takes the form fY(y)=a / y^b. Find the values of a and b.
1 answer