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The random variable X has a PDF of the form fX(x)={1x2,0,for x≥1,otherwise. Let Y=X2 . For y≥1 , the PDF of Y it takes the form...Asked by Mar
The random variable X has a PDF of the form
fX(x)= 1/x^2,for x≥1,
0,otherwise.
Let Y=X2. For y≥1, the PDF of Y it takes the form fY(y)=a / y^b. Find the values of a and b.
fX(x)= 1/x^2,for x≥1,
0,otherwise.
Let Y=X2. For y≥1, the PDF of Y it takes the form fY(y)=a / y^b. Find the values of a and b.
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a = 1/2 and b = 3
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