Question
you have 3 red sweaters 2 black sweaters. and 4 gray sweaters. you randomly pick one sweater, put it back, then randomly pick another. fin the probability that the first sweater chosen is red and the second is gray.
Answers
R_scott
the two selections are independent events
... all the sweaters are available for selection
9 total sweaters
p(red) = 3 / 9
p(gray) = 4 / 9
the probability of red then gray is the product of the individual probabilities
... all the sweaters are available for selection
9 total sweaters
p(red) = 3 / 9
p(gray) = 4 / 9
the probability of red then gray is the product of the individual probabilities