Asked by EYB
Two right-angle triangles △ABC and △BCD, have side BC in common, the hypotenuse of △ABC is side AB and the hypotenuse of △BCD is BC.
Given that AB = 18cm, CD = 6cm, and ∠A = 23°, determine the measure of θ = ∠BCD to the nearest degree.
Given that AB = 18cm, CD = 6cm, and ∠A = 23°, determine the measure of θ = ∠BCD to the nearest degree.
Answers
Answered by
Anonymous
sin 23 = BC / 18
so
BC = 7.033 cm
cos theta = 6/BC = 6 / 7.033 = 0.853
so
theta = cos^-1 (0.853) = 31 degrees
so
BC = 7.033 cm
cos theta = 6/BC = 6 / 7.033 = 0.853
so
theta = cos^-1 (0.853) = 31 degrees
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.