Question
The bases of a trapezoid are 25 and 15 respectively. The angles at the extremities of one base are 65 degree and 35 degree respectively find the two legs. pls help me, thank you!
Answers
oobleck
In trapezoid ABCD, let the altitude from C be CE and the altitude from D be DF. That is, FECD is a rectangle, with base FE.
Now collapse the trapezoid to eliminate the rectangle. Then CD=0 and AB=10 and you have a triangle with
angle C = 180-65-35 = 80°
10/sin80° = AD/sin35° = BC/sin65°
Now collapse the trapezoid to eliminate the rectangle. Then CD=0 and AB=10 and you have a triangle with
angle C = 180-65-35 = 80°
10/sin80° = AD/sin35° = BC/sin65°