In trapezoid ABCD, let the altitude from C be CE and the altitude from D be DF. That is, FECD is a rectangle, with base FE.
Now collapse the trapezoid to eliminate the rectangle. Then CD=0 and AB=10 and you have a triangle with
angle C = 180-65-35 = 80°
10/sin80° = AD/sin35° = BC/sin65°
The bases of a trapezoid are 25 and 15 respectively. The angles at the extremities of one base are 65 degree and 35 degree respectively find the two legs. pls help me, thank you!
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