Asked by Abrish

• A lock of mass 2g. has a constant velocity when it is pushed along a table by a force of 5N. when the push is increased to 9N: what is the acceleration?
Answered by oobleck
F=ma
so, 0.002a = (9-5)
a = 4/.002 = 2000 m/s^2

I suspect a typo.
Answered by Anonymous
2 kg maybe?
There are no AI answers yet. The ability to request AI answers is coming soon!