Asked by Blessing
A Town a is 300k due north of a town b.town c is 200k and a bearing of 133° from town a.how far is it from c to a
Answers
Answered by
oobleck
Did you draw a diagram? Using the law of cosines,
AC^2 = 300^2 + 200^2 - 2*300*200 cos47°
AC^2 = 300^2 + 200^2 - 2*300*200 cos47°
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