Question

. The E0 for the reaction Pb3(AsO4)2 (s) + 6e- ⇆ 3Pb(s) + 2AsO43- is -0.475 V. Calculate the solubility product constant for Pb3(AsO4)2 ?

Pb2 + + 2e- ⇆ Pb(s) E0=-0.126 V
Here is a worked example using AgI. Just follow it.
https://www.chemteam.info/Equilibrium/Calc-Ksp-from-cell-potential-values.html

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