Asked by Anonymous
What is the Gibbs Free energy for this galvanic cell in kJ/mol (hint: make sure your reaction is balanced correctly)
πΉ2(π)+2πββπΉβ(ππ) πΈ0πππ=2.87
π΄π3++3πββπ΄π(π ) πΈππππ=β1.66
πΉ2(π)+2πββπΉβ(ππ) πΈ0πππ=2.87
π΄π3++3πββπ΄π(π ) πΈππππ=β1.66
Answers
Answered by
DrBob222
dGo = -nFEo
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