Asked by lea
1. A chemistry student added 22.5 grams of aluminum at 85.00C to 115 grams of water at 23.00C in a perfect calorimeter. The final temperature of the aluminum-water mixture was 41.40C. Use the student’s data to calculate the specific heat of aluminum in joules/gram0C.
2. Calculate the final temperature that results from mixing 100.0 grams of water at 1000C with 106.0 grams of water at 24.80C
2. Calculate the final temperature that results from mixing 100.0 grams of water at 1000C with 106.0 grams of water at 24.80C
Answers
Answered by
DrBob222
[mass Al x specific heat Al x (Tfinal - Tinitial)] + [mass H2O x specific heat H2O x (Tfinal - Tinitial)] = 0
[22.5 g Al x sp. h. Al x (41.40 - 85.00)] + [115 x sp.h. H2O x (41.40 - 23.00)] = 0
You will need to look up the specific heat (sp.h.) of water.
The second problem is done the same way.
[22.5 g Al x sp. h. Al x (41.40 - 85.00)] + [115 x sp.h. H2O x (41.40 - 23.00)] = 0
You will need to look up the specific heat (sp.h.) of water.
The second problem is done the same way.
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