Asked by Anonymous
The area bounded by the curve ๐ฆ = 3 โ 2๐ฅ + ๐ฅ
2 and line ๐ฆ = 3 is revolved about the line ๐ฆ =3.
Find the volume generated.
2 and line ๐ฆ = 3 is revolved about the line ๐ฆ =3.
Find the volume generated.
Answers
Answered by
oobleck
the curves intersect at (0,3) and (2,3)
using shells of thickness dx,
v = โซ[0,2] ฯr^2 dx
where r=3-y
v = โซ[0,2] ฯ(3 - (x^2-2x+3))^2 dx = 16ฯ/15
Using shells of thickness dy, and the symmetry about the line x=1,
v = โซ[2,3] 2ฯrh dy
where r = 3-y and h = 1-x
v = 2โซ[2,3] 2ฯ(3-y)โ(y-2) dy = 16ฯ/15
using shells of thickness dx,
v = โซ[0,2] ฯr^2 dx
where r=3-y
v = โซ[0,2] ฯ(3 - (x^2-2x+3))^2 dx = 16ฯ/15
Using shells of thickness dy, and the symmetry about the line x=1,
v = โซ[2,3] 2ฯrh dy
where r = 3-y and h = 1-x
v = 2โซ[2,3] 2ฯ(3-y)โ(y-2) dy = 16ฯ/15
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