Asked by Anonymous

The area bounded by the curve ๐‘ฆ = 3 โˆ’ 2๐‘ฅ + ๐‘ฅ
2 and line ๐‘ฆ = 3 is revolved about the line ๐‘ฆ =3.
Find the volume generated.

Answers

Answered by oobleck
the curves intersect at (0,3) and (2,3)
using shells of thickness dx,
v = โˆซ[0,2] ฯ€r^2 dx
where r=3-y
v = โˆซ[0,2] ฯ€(3 - (x^2-2x+3))^2 dx = 16ฯ€/15

Using shells of thickness dy, and the symmetry about the line x=1,
v = โˆซ[2,3] 2ฯ€rh dy
where r = 3-y and h = 1-x
v = 2โˆซ[2,3] 2ฯ€(3-y)โˆš(y-2) dy = 16ฯ€/15
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