Asked by Nevaeh
in the diagram, the balls velocity is 6 m/s, and the height of the ramp is 1 m. what will the balls velocity be at the top of the ramp? ignore friction.
Answers
Answered by
oobleck
KE at the start: 1/2 mv^2 = 18m
PE at the top: mgh = 9.8m
difference: 8.2m = 1/2 mv^2
so find v,
PE at the top: mgh = 9.8m
difference: 8.2m = 1/2 mv^2
so find v,
Answered by
Sara
4 m/s is the correct answer
Answered by
Giraffe Lover
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