Asked by Shundria
The arch of the bridge below is an ellipse, a semi-ellipse"As shown in the figure below, the arch is 164 m long and has a height of 52 m at the center. The height of the arch is 11 m at point p. Find the distance from p to the center. Round your answer to the nearest hundredth. Do not round any intermediate computations.
Answers
Answered by
oobleck
Let the center of the ellipse be at (0,0). Then you have
a = 164/2 = 82
b = 52
so the equation is
x^2/82^2 + y^2/52^2 = 1
So now you just have to solve for p.
p^2/82^2 + 11^2/52^2 = 1
a = 164/2 = 82
b = 52
so the equation is
x^2/82^2 + y^2/52^2 = 1
So now you just have to solve for p.
p^2/82^2 + 11^2/52^2 = 1
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