stop using x as both a variable and an operator. I see this question was already interpreted and answered, but now you post it again. So maybe you meant (p*q)(5). If so, then
p(x)*q(x) = (-x-1)(-2x^2-2) = 2(x^3 + x^2 + x + 1) = 2(x^4 - 1)/(x-1)
(p*q)(5) = 2(624)/4 = 312
Or, p(5) = -6, q(5) = -52 so (p*q)(5) = (-6)*(-52) = 312
and, since multiplication is commutative, this is also (q*p)(5)
Suppose that the functions p and q are defined as follows.
p(x)=-x-1
q(x)=-2x^2-2
Find the following.
(pxq)(5)
(qxp)(5)
2 answers
so, maybe you did mean it the way that it was explained to "Froggy" a couple of questions below.