Asked by Adiii
What is the percentage yield if 110.6 g of malachite are formed when 1.5 moles of copper sulfate reacts with an excess of sodium carbonate?
Answers
Answered by
oobleck
determine how many moles you expected.
divide yield by expectation
divide yield by expectation
Answered by
Adiii
But how would you find the expectation?
Answered by
DrBob222
CuSO4 + Na2CO3 ==> CuCO3 + Na2SO4
1.5 mols CuSO4 will produce 1.5 moles of CuCO3 theoretically and 1.5 mols = 1.5 x 123.5 = 185 g CuCO3. This is the expected yield at 100%.
% yield = (actual yield/expected yield)*100 = (110.6/185)*100 = ?
1.5 mols CuSO4 will produce 1.5 moles of CuCO3 theoretically and 1.5 mols = 1.5 x 123.5 = 185 g CuCO3. This is the expected yield at 100%.
% yield = (actual yield/expected yield)*100 = (110.6/185)*100 = ?
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