Asked by Aimee
If you are given .060m. sugar (glucose-C6H12O6), .030m. AlCl3 and .025m. NaOH.
How do you figur out lowest boiling point and lowest vapor pressure of the given solutions?
How do you figur out lowest boiling point and lowest vapor pressure of the given solutions?
Answers
Answered by
DrBob222
Lowest boiling point.
delta T = i*Kb*m
Since Kb is a constant, you only need to do i*molality.
i = # dissolved particles. m is molality.
delta T will be the lowest for the smallest product of i*m
delta T = i*Kb*m
Since Kb is a constant, you only need to do i*molality.
i = # dissolved particles. m is molality.
delta T will be the lowest for the smallest product of i*m
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