The base of a triangle is 1 cm more than 3 times its height. If the area of the triangle is 15 cm^2. Determine the length of the base and the height of this triangle.
3 answers
I just did this for you a minute or two ago. Read your first post before doing it again!
The vertex of the quadratic function y = 2x^2+8x + c is (x, 3) .
On Blank 1, state the value of x-coordinate of the vertex
On Blank 2, state the value of m
On Blank 1, state the value of x-coordinate of the vertex
On Blank 2, state the value of m
the vertex is at x = -b/2a
so, x = -8/4 = -2
I have no idea what m is, but the above answer means that c=11
check
y = 2x^2+8x+c
= 2(x^2+4x) + c
= 2(x^2+4x+4) + c-2*4
= 2(x+2)^2 + c-8
so
3 = c-8
c = 11
so, x = -8/4 = -2
I have no idea what m is, but the above answer means that c=11
check
y = 2x^2+8x+c
= 2(x^2+4x) + c
= 2(x^2+4x+4) + c-2*4
= 2(x+2)^2 + c-8
so
3 = c-8
c = 11