Asked by William Dane
Consider the reaction
4 KO2(s) + 2 CO2(g) →
2 K2CO3(s) + 3 O2(g).
How much KO2 is needed to react with 75.0 L
of carbon dioxide at STP?
4 KO2(s) + 2 CO2(g) →
2 K2CO3(s) + 3 O2(g).
How much KO2 is needed to react with 75.0 L
of carbon dioxide at STP?
Answers
Answered by
DrBob222
4KO2(s) + 2CO2(g) → 2K2CO3(s) + 3O2(g).
mols CO2 = 75/22.4 = 3.34
mols KO2 needed = 3.34 mols CO2 x (4 mols KO2/2 mols CO2) =?
The grams KO2 = mols KO2 x molar mass KO2
Post your work if you get stuck.
mols CO2 = 75/22.4 = 3.34
mols KO2 needed = 3.34 mols CO2 x (4 mols KO2/2 mols CO2) =?
The grams KO2 = mols KO2 x molar mass KO2
Post your work if you get stuck.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.