Asked by Christopher
                A cylindrical iron rod 8cm height and 6cm in diameter stands in a cylindrical tin 12cm in diameter water is poured into the tin unfit it's depth is 8cm how far until the level drop when the rod is removed
            
            
        Answers
                    Answered by
            Christopher
            
    Waiting
    
                    Answered by
            oobleck
            
    the volume of water displaced by the rod is
v = πr^2 h = π * 3^2 * 8 = 72π cm^3
The drop in water level is the rod volume divided by the cross-section area of the tin, or
72π/(π*6^2) = 2 cm
    
v = πr^2 h = π * 3^2 * 8 = 72π cm^3
The drop in water level is the rod volume divided by the cross-section area of the tin, or
72π/(π*6^2) = 2 cm
                    Answered by
            Victor
            
    Thanks
    
                    Answered by
            Perpetual
            
    Thanks 😊😊
    
                    Answered by
            Ayomide
            
    This helps thanks😊😊
    
                    Answered by
            GBEMZ GOLD
            
    Intresting
    
                    Answered by
            GBEMZ GOLD
            
    It really helps I love u guy
    
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