Asked by Susan
                Find:
1. f(x)= (6x^2-2)
_______
x^3
2. f(x)= (x^2-4)^1/3
A. Domain
B. Intercepts
C. Asymptotes, behaviour and check for crossing where applicable
D. Critical Number(s)
E. Interval of Increase/Decrease
F. Local Extrema
G. Concavity and Points of Inflection
Thank you!!
            
            
        1. f(x)= (6x^2-2)
_______
x^3
2. f(x)= (x^2-4)^1/3
A. Domain
B. Intercepts
C. Asymptotes, behaviour and check for crossing where applicable
D. Critical Number(s)
E. Interval of Increase/Decrease
F. Local Extrema
G. Concavity and Points of Inflection
Thank you!!
Answers
                    Answered by
            oobleck
            
    A. #1 -- all reals except where the denominator is zero
#2. all reals, since it's an odd root
B. #1 - where the numerator is zero
#2. so easy
C. #1 where the denominator is zero
#2 none
D. #1 f' = 6(1-x^2)/x^4
#2. f' = 2x/(3((x^2-4)^2/3) where is the numerator = 0?
E. See D, and check sign of f'
F. See D and check where f'=0
G #1. f" = 12(x^2-2)/x^5
#2. f" = -2(x^2+12)/(9((x^2-4)^5/3)
inflection where f"=0
concave up where f" > 0
Check your results by typing in the functions at wolframalpha.com
    
#2. all reals, since it's an odd root
B. #1 - where the numerator is zero
#2. so easy
C. #1 where the denominator is zero
#2 none
D. #1 f' = 6(1-x^2)/x^4
#2. f' = 2x/(3((x^2-4)^2/3) where is the numerator = 0?
E. See D, and check sign of f'
F. See D and check where f'=0
G #1. f" = 12(x^2-2)/x^5
#2. f" = -2(x^2+12)/(9((x^2-4)^5/3)
inflection where f"=0
concave up where f" > 0
Check your results by typing in the functions at wolframalpha.com
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.