Question

An object, let go from rest at height h, travels 0.33h during its first second. Find the average velocity of the entire free fall.

Answer 1

the acceleration is a = -0.33
so the height y = h - 0.165 t^2
so find how long it takes to fall (solve y=0 for t)
and the average velocity is -h/t

Answer 2

average velocity during its first second is ... 0.33h/s

its starting from rest , so the velocity after one second is ... 0.66h/s
... so the acceleration is ... 0.66h/s^2

h = 1/2 * 0.66 h/s^2 * t^2 ... 2 s^2 = 0.66 t^2 ... t = √(2 / 0.66) s

average velocity = h / t