Asked by Cai Nix
A fountain at a city park shoots a stream of water vertically from the ground. The function y=-8x^2+16 models the height of the stream of water in feet after x seconds.
A. What is the maximum height of the stream of water?
B. At what time does the stream of water reach its maximum height?
C. For how many seconds does the stream of water appear above ground?
A. What is the maximum height of the stream of water?
B. At what time does the stream of water reach its maximum height?
C. For how many seconds does the stream of water appear above ground?
Answers
Answered by
Cai Nix
hellp me
Answered by
Cai Nix
hurry
Answered by
oobleck
This is a bogus equation. It describes a pet of water being shot horizontally, not vertically. It's missing an x term, which indicates the initial upward velocity.
B. As with all quadratics, the vertex is at x = -b/2a
A. See B above
C. solve for x in y=0
B. As with all quadratics, the vertex is at x = -b/2a
A. See B above
C. solve for x in y=0
Answered by
Anonymous
The equation for height above launch point in feet in time t is
y = Vi t - 16 t^2 where Vi is the initial speed up.
Either you have some strange typos or your math book does not do physics.
y = Vi t - 16 t^2 where Vi is the initial speed up.
Either you have some strange typos or your math book does not do physics.
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