Asked by Cai Nix

A fountain at a city park shoots a stream of water vertically from the ground. The function y=-8x^2+16 models the height of the stream of water in feet after x seconds.

A. What is the maximum height of the stream of water?



B. At what time does the stream of water reach its maximum height?



C. For how many seconds does the stream of water appear above ground?

Answers

Answered by Cai Nix
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Answered by Cai Nix
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Answered by oobleck
This is a bogus equation. It describes a pet of water being shot horizontally, not vertically. It's missing an x term, which indicates the initial upward velocity.

B. As with all quadratics, the vertex is at x = -b/2a
A. See B above
C. solve for x in y=0
Answered by Anonymous
The equation for height above launch point in feet in time t is
y = Vi t - 16 t^2 where Vi is the initial speed up.
Either you have some strange typos or your math book does not do physics.
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