Asked by tdfg

Sue had $5.65 worth of quarters and dimes. There were 3 more quarters than dimes. How many quarters were there?

Answers

Answered by oobleck
10(q-3) + 25q = 565
so solve for q
Answered by PsyDAG
d = Q - 3

.25Q + .10d = .25Q + .10(Q-3) = $5.65

Solve for Q.
Answered by CookieCrumbs
number of dimes = y
number of quarters = y+3

10y + 25(y+3) = 565

solve for y

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