Sue had $5.65 worth of quarters and dimes. There were 3 more quarters than dimes. How many quarters were there?

Answer 1

10(q-3) + 25q = 565
so solve for q

Answer 2

d = Q - 3

.25Q + .10d = .25Q + .10(Q-3) = $5.65

Solve for Q.

Answer 3

number of dimes = y
number of quarters = y+3

10y + 25(y+3) = 565

solve for y