Asked by Chibuike

If 465 cm³ of sulphur(IV)oxide,can be diffuse through porous partition in 30s how long will(a) an equal volume , (b)620cm³ of hydrogen sulphide take to diffuse through the same partition ?(H=1,S=32,O=16)
Answered by DrBob222
part a.
mm = molar mass
(rate 1)/(rate 2) = sqrt (mm 2/mm 1)
Substitute the following:
rate 1 = rate SO2 = 465 cc/30 sec
rate 2 = rate H2S = 465 cc/x sec
mm 1 = molar mass SO2 = 64
mm 2 = molar mass H2S = 34
Solve for x sec.
part b. Substitute the new numbers.
Post your work if you get stuck.
Answered by Anonymous
Pls I am confused
I don't understand
Answered by Anonymous
I dont understand.please go straight to the point😢
Answered by peace
how will I substitute the new answer please I am confused please explain more
Answered by Chidi deborah
I am confused about the answer to the question above
Answered by Anonymous
I am confuse, explain more
Answered by Damilola
I am confused
Answered by DEBORAH
Please l dont understand go straight to the point and make your explanation clear
Answered by adida Godswill
th2/to2=√mo2/mo2
There are no AI answers yet. The ability to request AI answers is coming soon!