Question
A student pours a 10.0mL sample of a solution containing HC2H3O2(pKa=4.8) and NaC2H3O2 into a test tube. The student adds a few drops of bromocresol green to the test tube and observes a yellow color, which indicates that the pH of the solution is less than 3.8. Based on this result, which of the following is true about the relative concentrations of HC2H3O2 and NaC2H3O2 in the original solution?
A. [HC2H3O2]>[NaC2H3O2]
B. [HC2H3O2]=[NaC2H3O2]
C. [HC2H3O2]<[NaC2H3O2]
D. The relative concentrations cannot be determined without knowing the value of pKb for C2H3O2−.
A. [HC2H3O2]>[NaC2H3O2]
B. [HC2H3O2]=[NaC2H3O2]
C. [HC2H3O2]<[NaC2H3O2]
D. The relative concentrations cannot be determined without knowing the value of pKb for C2H3O2−.
Answers
pH = pKa + log [(acetate)/(acetic acid)]
3.8 = 4.8 + log base/acid
-1.0 = log base/acied
base/acid = 10^-1 = 0.1 or
base = 0.1*acid
so base (NaC2H3O2) < acid (HC2HO2)
3.8 = 4.8 + log base/acid
-1.0 = log base/acied
base/acid = 10^-1 = 0.1 or
base = 0.1*acid
so base (NaC2H3O2) < acid (HC2HO2)
Related Questions
i am completely lost, i confused myself.
i need to find the concentration of HC2H3O2
HC2H3O2 +...
Calculate [H3O] in the following solutions.
5.15x10-2M HCl and 7.62x10-2M NaC2H3O2
Responses...
a solution is made by combining 5 mL of .2M HC2H3O2, 5 mL of .2M NaC2H3O2, and 10 ml of water. calcu...
What is the Ka value of acetic acid from the pH of the buffered solution? pH=4.39 of 25ml of HC2H3O2...