Asked by math
A square is inscribed in the circle (x-1)^2 + (y+1)^2 = 8. If one vertex of this square is the point (-1,1) then find the other vertices of this square.
Answers
Answered by
R_scott
the center of the circle (and the square) is ... (1 , -1)
the diagonal of the square is ... 2√8 = 4√2
... so the side of the square is 4
vertices are ... (-1 , -3) , (3 , 1) , (3 , -3)
the diagonal of the square is ... 2√8 = 4√2
... so the side of the square is 4
vertices are ... (-1 , -3) , (3 , 1) , (3 , -3)
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