a number of ways to do this
he must have put 1/10 of 10.8g in the sample, then diluted it to a volume of .050liters
Molarity=10.8/10 * 1/molmass*1/.050
where molmass is the molmass of ammonium nitrate.
10.0 g of NH4NO3 is dissolved in enough water to make 450.0 mL of solution. What is the molarity of the solution?
2 answers
NOPE, that is not one of the ways to do this problem. The correct way to do this is as follows:
M = mols/L of solution. L is 0.45 from the problem. Find mols by
moles = grams/molar mass = 10.8/80 = xx
So M = mols/L = xx from above/0.45 = ?
M = mols/L of solution. L is 0.45 from the problem. Find mols by
moles = grams/molar mass = 10.8/80 = xx
So M = mols/L = xx from above/0.45 = ?