Question

a student standing in an elevator at rest notices that her pendulum has a frequency of oscillation of 0.5 Hz.
a. what is the length of the pendulum's string?
b. the elevator starts to accelerate upwards. what effect will this have on the oscillation? explain. ​

Answer 1

f = (1/2pi) sqrt (g/L)
0.5 (2)(pi) = sqrt (9.81 / L)
3.14159 = sqrt (9.81/L)
9.81/L = 9.86959
L = .995 meter
bigger g, bigger f

Answer 2

What do the bigger g and f mean.