Mario rolls a 6-sided die 60 times. About how many times should he expect it to land on an 2?
2 answers
Probability of landing on 2 is 1/6. Multiply that by 60.
The probability of one roll for each of the 6 possible numbers, including number 2, is 1 / 6
After 1 roll probability = 1 / 6
After 2 rolls probability = 2 ∙ 1 / 6
After 3 rolls probability = 3 ∙ 1 / 6
etc.
After 60 rolls probability = 60 ∙ 1 / 6 = 60 / 6 = 10
After 1 roll probability = 1 / 6
After 2 rolls probability = 2 ∙ 1 / 6
After 3 rolls probability = 3 ∙ 1 / 6
etc.
After 60 rolls probability = 60 ∙ 1 / 6 = 60 / 6 = 10