Asked by Sekou
If y varies inversely as x + 2 and y=48 when x=10, find x when y=30
Answers
Answered by
oobleck
y = k/(x+2)
so, y(x+2) = k is constant
You want x such that
30/(x+2) = 48/(10+2)
so, y(x+2) = k is constant
You want x such that
30/(x+2) = 48/(10+2)
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