Question

A long, thin rod with moment of inertia I=2 kg•m2 is free to rotate about an axis passing through the midpoint of the rod. The rod begins rotating from rest at time t= 0 s, accelerating constantly so that it has a rotational velocity of 4𝜋 rad/ s after rotating through two complete revolutions. What is the rod's angular momentum at this point?

Answer 1

angular momentum = moment of inertia * angular velocity
= 2 kg m^2 * 4 pi rad/s
= 8 pi