Asked by holland
Solve the equation 3x^2+7x+14=−7x to the nearest tenth.
Answers
Answered by
oobleck
3x^2+7x+14=−7x
3x^2+14x+14 = 0
Now just use the quadratic formula.
x = (-14±√(14^2 - 4*3*14))/(2*3) = (-7±√7)/3
3x^2+14x+14 = 0
Now just use the quadratic formula.
x = (-14±√(14^2 - 4*3*14))/(2*3) = (-7±√7)/3
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