Question
You drive a car 1500 ft to the east, then 2500 ft to the north. If
the trip took 3.0 minutes, what were the direction and magnitude of your average velocity?
the trip took 3.0 minutes, what were the direction and magnitude of your average velocity?
Answers
final displacement: d = 500√34
avg speed: d/3 ft/min
direction: tanθ = 2500/1500 = 5/3
avg speed: d/3 ft/min
direction: tanθ = 2500/1500 = 5/3
direction of average velocity is 59 north of east
and magnitude of average velocity is 4.2 m/s
and magnitude of average velocity is 4.2 m/s
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