Asked by Nousheen
A sample of gas is collected over water at a temperature of 45.0 oC when barometric pressure reading is 742.0 torr. What is the partial pressure of the dry gas?
Answers
Answered by
Helper
This site tells me that vapour pressure of water at 35.0 ∘C = 42.2⋅mm⋅Hg.
Explanation:
P
collected
=P gas+P SVP, P SVP is given above, and is called the saturated vapour pressure. This should have been quoted with the question.
Thus
Pgas≅700⋅mm⋅Hg.
Explanation:
P
collected
=P gas+P SVP, P SVP is given above, and is called the saturated vapour pressure. This should have been quoted with the question.
Thus
Pgas≅700⋅mm⋅Hg.
Answered by
DrBob222
Ptotal = Pgas + PH2O.
Ptotal = 742.0
pH2O = ? Look up the vapor pressure of H2O @ 45.0 degrees C. You should have that in your text/notes or you can find it on the web. Note that Helper used 35.0 but the problem gives 45.0 C.
Ptotal = 742.0
pH2O = ? Look up the vapor pressure of H2O @ 45.0 degrees C. You should have that in your text/notes or you can find it on the web. Note that Helper used 35.0 but the problem gives 45.0 C.