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Find y' if

y = ln(5x^2 + 9y^2).

1 answer

use the chain rule
y' = 1/(5x^2 + 9y^2) * (10x + 18yy')
y' (1 - 1/(5x^2 + 9y^2)(18y)) = 10x/(5x^2 + 9y^2)
y' = 180xy / (18y(5x^2+9y^2) - 1)
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