Asked by Gracie
Polar Equation Question
The figure above shows the graph of the polar curve r=1−2cosθ for 0≤θ≤π and the unit circle r=1.
(a) Find the area of the shaded region in the figure.
Question 2
(b) Find the slope of the line tangent to the polar curve r=1−2cosθ at the point where x=−2. Show the computations that lead to your answer.
Question 3
(c) A particle moves along the polar curve r=1−2cosθ so that dθdt=2. Find the value of drdt at θ=2π3, and interpret your answer in terms of the motion of the particle.
Can’t post diagram because it is a url
The figure above shows the graph of the polar curve r=1−2cosθ for 0≤θ≤π and the unit circle r=1.
(a) Find the area of the shaded region in the figure.
Question 2
(b) Find the slope of the line tangent to the polar curve r=1−2cosθ at the point where x=−2. Show the computations that lead to your answer.
Question 3
(c) A particle moves along the polar curve r=1−2cosθ so that dθdt=2. Find the value of drdt at θ=2π3, and interpret your answer in terms of the motion of the particle.
Can’t post diagram because it is a url
Answers
Answered by
PsyDAG
If you can't post the diagram, we can't post answers.
Answered by
oobleck
(a) recall that A = ∫ 1/2 r^2 dθ
(b) dy/dx = (dy/dθ) / (dx/dθ)
= (r' sinθ + r cosθ)/(r'cosθ - r sinθ)
so find r and θ when x=2, and plug and chug.
(c) dr/dt = 2sinθ dθ/dt = 2(√3/2)(2)
(b) dy/dx = (dy/dθ) / (dx/dθ)
= (r' sinθ + r cosθ)/(r'cosθ - r sinθ)
so find r and θ when x=2, and plug and chug.
(c) dr/dt = 2sinθ dθ/dt = 2(√3/2)(2)
Answered by
Gracie
the diagram is 1-2costheta graphed from 0 to pi and a circle with a radius of 1. The shaded area is almost 3/4ths the unit circle except for the slivers that 1-2costheta cuts thru the first and third quadrants
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.