Asked by Harikishore
On August 2, 1971, Astronaut David Scott, while standing on the surface of the Moon, dropped a 1.3-kg hammer and a 0.030-kg falcon feather from a height of 1.6 . Both objects hit the Moon’s surface 1.4 after being released. What is the acceleration due to gravity on the surface of the Moon?
Answers
Answered by
Anonymous
about one sixth of g on earth (to check)
height = (1/2) G t^2
3.2 = G (1.4)^2
G = 1.63 m/s^2
to check g/6 = 9.81/6 = 1.635
height = (1/2) G t^2
3.2 = G (1.4)^2
G = 1.63 m/s^2
to check g/6 = 9.81/6 = 1.635
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