Question

Calculate the total number of moles of gas produced from the decomposition of 10.0 g of guanidinium nitrate

I know that the equation for the decomposition is CH6N4O3 (s) → 3 H2O (g) + 2 N2 (g) + C but I don't know where to go from here.
figure the moles of CH6N4O3 in 10.0g
The equation says that you will get 5 times that many moles of gas (3H2O and 2N2)
mol of CH6N4O3 is 12+6+(4*14)+(3*16) grams

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