Asked by Michelle
                The half-life of a radioactive isotope is 10 days. If 3.2 kg are present now, how much was present 30 days previous?
            
            
        Answers
                    Answered by
            oobleck
            
    30 days is 3 half-lives. So, there is 1/2^3 = 1/8 as much now as 30 days ago.
That means you had 3.2*8 = ___ kg then.
A(1/2)^(30/10) = 3.2
    
That means you had 3.2*8 = ___ kg then.
A(1/2)^(30/10) = 3.2
                    Answered by
            I got no time
            
    I don't really get it but the only thing that I think might help is:
10/3.2=a
a*30= answer
    
10/3.2=a
a*30= answer
                    Answered by
            I got no time
            
    oh- thx
    
                    Answered by
            Michelle
            
    That is not one of the answer choices. The choices are 12.8, 25.6, 6.4, 51.2
    
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