A 45.87-kg crate is suspended by a spring with a spring constant of 6000 N/m on a frictionless surface at an angle of 30 °. Find the stretch of the spring in meters.

Answer 1

weight= m g = 45.87 * 9.81 = 450 Newtons
weight component parallel to slope = 450 sin 30 = 225 N
F = k x
225 = 6000 x
x = 0.0375 meters (or 3.75 centimeters or about an inch and a half)