SO2(g) + ½O2(g) ==> SO3 (g) Kc = 56
SO3(g) ==> SO2(g) + ½O2(g) Kc = 1/56
2SO2(g ==> 2SO2(g) + O2(g) Kc = (1/56)^2
If you will write out the Kc expressions for 1, 2, and 3 above you will see where the reciprocal and reciprocal squared come in.
If the reaction SO2(g) + ½O2(g) SO3 (g) has the equilibrium constant Kc = 56, then what is the value of Kc for the following reaction?
2SO3(g) 2SO2(g) + O2(g)
A. 3.2 × 10-4
B. -112
C. 8.9 × 10-3
D. 56
3 answers
Bob dude I swear
The answer is A
1 answer