Asked by Akdechi

If the reaction SO2(g) + ½O2(g) SO3 (g) has the equilibrium constant Kc = 56, then what is the value of Kc for the following reaction?

2SO3(g) 2SO2(g) + O2(g)

A. 3.2 × 10-4


B. -112


C. 8.9 × 10-3


D. 56
Answered by DrBob222
SO2(g) + ½O2(g) ==> SO3 (g) Kc = 56
SO3(g) ==> SO2(g) + ½O2(g) Kc = 1/56
2SO2(g ==> 2SO2(g) + O2(g) Kc = (1/56)^2

If you will write out the Kc expressions for 1, 2, and 3 above you will see where the reciprocal and reciprocal squared come in.
Answered by Drbob hater
Bob dude I swear
Answered by Anonymous
The answer is A
There are no AI answers yet. The ability to request AI answers is coming soon!