Asked by need homework help please
                Find the value of a so that the function f(x)=xe^(ax) has a critical point at x=8.
a =
            
        a =
Answers
                    Answered by
            oobleck
            
    didn't we already do one almost like this?
f'(x) = e^x (1+ax)
now, you want to find where 1+8a = 0
    
f'(x) = e^x (1+ax)
now, you want to find where 1+8a = 0
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