Asked by Leah
Given: Triangles ABC and DBC are isosceles, m∠BDC = 30°, and m∠ABD = 155°. Find m∠ABC, m∠BAC, and m∠DBC.
Answers
Answered by
oobleck
m∠DBC = (180-30)/2 = 75°
m∠ABC = m∠ABD - m∠DBC = 155-75 = 80°
so m∠A = (180 - 2*80) = 20°
Now you know all the angles.
m∠ABC = m∠ABD - m∠DBC = 155-75 = 80°
so m∠A = (180 - 2*80) = 20°
Now you know all the angles.
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