Ask a New Question

Asked by Anonymous

A particle is moving along a line so that if v feet per second is the velocity of the particle at t second, then v= t^2-t+1/((t+2)^2(t^2+1)). Find a formula for the distance traveled by the particle from the time when ๐‘ก = 0 ๐‘ก๐‘œ ๐‘กโ„Ž๐‘’ ๐‘ก๐‘–๐‘š๐‘’ ๐‘คโ„Ž๐‘’๐‘› ๐‘ก = t sub 1
4 years ago

Answers

Answered by oobleck
that would, of course, be
โˆซ[0,t_1] v(t) dt
You'll have to use partial fractions to do this one.
4 years ago

Related Questions

A particle is moving along the curve y= 3 \sqrt{3 x + 4}. As the particle passes through the point (... A particle is moving along the x-axis so that at time t its acceleration is a(t)=รฐcos(รฐt) At time... A particle is moving along a horizontal straight line. The graph of the position function (the dista... A particle is moving along the x-axis so that its position at t โ‰ฅ 0 is given by s(t)=(t)In(2t). Fin... A particle is moving along the x-axis so that its position at t>=0 is given by s(t)=(t)ln(5t). Find... An 80g particle moving with an initial velocity of (50m/s)รฎ strikes and sticks to a 60g particle mo... 1 A particle is moving in a stright line with the position at any time t is given by s= tยณโ€“9tยฒ+3t+1,... A particle is moving as given by the data below 4sin(t)-3cos(t); s(0)=0
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use