A particle is moving along a line so that if v feet per second is the velocity of the particle at t second, then v= t^2-t+1/((t+2)^2(t^2+1)). Find a formula for the distance traveled by the particle from the time when ๐‘ก = 0 ๐‘ก๐‘œ ๐‘กโ„Ž๐‘’ ๐‘ก๐‘–๐‘š๐‘’ ๐‘คโ„Ž๐‘’๐‘› ๐‘ก = t sub 1

1 answer

that would, of course, be
โˆซ[0,t_1] v(t) dt
You'll have to use partial fractions to do this one.
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