The region in the first quadrant bounded by the curve ๐‘ฆ = cos ๐‘ฅ ๐‘Ž๐‘›๐‘‘ ๐‘กโ„Ž๐‘’ ๐‘™๐‘–๐‘›๐‘’๐‘  ๐‘ฆ = 1 ๐‘Ž๐‘›๐‘‘ ๐‘ฅ =1/2๐œ‹ ๐‘–๐‘  ๐‘Ÿ๐‘’๐‘ฃ๐‘œ๐‘™๐‘ฃ๐‘’๐‘‘ ๐‘Ž๐‘๐‘œ๐‘ข๐‘ก ๐‘กโ„Ž๐‘’ ๐‘กโ„Ž๐‘’ ๐‘™๐‘–๐‘›๐‘’ ๐‘ฅ =1/2๐œ‹. Find the volume of the solid generated.

1 answer

using cylinders of thickness dx, we have
v = โˆซ[0,ฯ€/2] 2ฯ€rh dx
where r = ฯ€/2 - x and h = 1-cosx
v = โˆซ[0,ฯ€/2] 2ฯ€(ฯ€/2 - x)(1-cosx) dx = ฯ€/4 (ฯ€^2 - 8) โ‰ˆ 1.4684