Asked by Porter
PLZ HELP THIS IS DUE IN 2HRS
A clay ball (mass = 0.25kg) has a rightward momentum of +1.75 kg∙m/s. A second clay ball (mass = 0.25 kg) has a leftward momentum of -1.75 kg∙m/s. The two collide, stick together, and come to a complete stop after the collision.
What was the total energy of the system before the collision?
What was the total energy of the system After the collision?
my choices are 6.13 J
12.25 J
Not enough information to determine
0 J
A clay ball (mass = 0.25kg) has a rightward momentum of +1.75 kg∙m/s. A second clay ball (mass = 0.25 kg) has a leftward momentum of -1.75 kg∙m/s. The two collide, stick together, and come to a complete stop after the collision.
What was the total energy of the system before the collision?
What was the total energy of the system After the collision?
my choices are 6.13 J
12.25 J
Not enough information to determine
0 J
Answers
Answered by
oobleck
conserve momentum.
1.75 - 1.75 = 0
so the stuck-together balls have completely stopped.
what does that tell you abut the final energy of the system?
note that when the balls are moving, momentum p = mv so
KE = 1/2 mv^2 = 1/2 m (p/m)^2 = p^2 / 2m
1.75 - 1.75 = 0
so the stuck-together balls have completely stopped.
what does that tell you abut the final energy of the system?
note that when the balls are moving, momentum p = mv so
KE = 1/2 mv^2 = 1/2 m (p/m)^2 = p^2 / 2m
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